# Two Part Motion

1. Sep 24, 2006

### Shane_K

I have a question which reads as follows:
After a long time apart, a young couple in love are running towards each other in the hallways of an airport. They are 30.0m apart. The husband is accelerating from rest at a rate of 0.7m/s2 (2 is squared), and the wife was moving at 3.4m/s and maintains her speed. How much time passes before they are finally together?

I just need help gathering the info from the question.
What I have so far:
Husband
-v1=0m/s
-acceleration=0.7m/s2 (2 is squared)
-distance=30.0m
-time=?

Wife
-v1=3.4m/s
-distance=30.0m
-t=?

2. Sep 25, 2006

### Staff: Mentor

One may infer from the problem that the husband starts accelerating when his wife is 30 m from him. During the same period of time, each is traveling to some common point.

Let x be the distance traveled by the wife, and then knowing the velocity that the wife travels, 3.4 m/s, the distance as a function of time is simply x = 3.4 t (t in seconds).

In the same time, when they meet, the husband must have traveled 30-x.