Can anyone tell me if this concentration calculation is correct please, its my first attempt and a bit unsure.(adsbygoogle = window.adsbygoogle || []).push({});

Two point determination of cocaine sample

Cocaine (mg/ml) Average peak height

0.015 13059

0.20 98496

Unknown (2mg/ml) 61136General equation Y = mx + c

Equation 1 standard 1: 13059 = 0.015m + c

Equation 2 standard 2: 98496 = 0.20m + c

98496 – 13059 = 85437

0.20 – 0.015 = 0.185

therefore 85437 = 0.185m + 0

85437 / 0.185 = m

m = 461821.62

c = 13059 = (0.015 X 461821.62)

13059 – (0.015 X 461821.62) = 6132

So, Y = 461821.62 X + 6132

Unknown therefore:

61136 = 461821.62 X + 0

= 61136 – 0 / 461821.62 = 0.13

0.13 / 2 X 100 =6.6%

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# Homework Help: Two point estimates am i correct

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