- #1
Sure. Note that you can drive a port with a current source rather than a voltage source. This might make some of your work easier, not having to fiddle about with voltage dividers and determining the input current separately.Calculate the characteristic impedance (Z0) of the two port network shown below:
In this example :
R1 = 40 ohm
R2 = 40 ohm
R3 = 20 ohm
V1 = I1 (R1+R2)
Then, Z11 = V1/I1 = R1+R3 = 40+20 = 60 ohm
V2 = V1 (R3 / R1+R3) = I1 (R3+ R1) (R3 / (R1+R3)) = I1 R3
Then, Z21 = V2 / I1 = R3 = 20 ohm
Am I correct so far?
The part in red is incorrect. You have Zor = sqrt(Zoc) + ZscI found the way to calculate T network, where Zor is a characteristic impedance
Zoc= R1 + R2 = 40 + 20 = 60Ω
Zso = (R1 * R2 ) /( R1 + R2 ) + R1
Zso= (40 + 20) / (40+ 20 ) + 40
Zso= 800/ 60 + 40 = 13.333+ 40 = 53.333Ω
Zor= √ Zoc Zsc = √60 + 53.333= √ 113.333 = 10.645 Ω
I hope im on right path this time