flyingpig
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Two questions about rotation of this "line"
3x^2 - 2\sqrt{3}xy +y^2 = 1
x = x'\cos\alpha - y'\sin\alpha
y = x'\sin\alpha + y'\cos\alpha
The discriminant test is
4(3) - 4(3)(1) = 0
Supposed to be a parabola, instead we get lines.
One other thing
Supposed that in
cot2\alpha = \frac{A - C}{B}
And then we get that \alpha < 0, can that happen? Can we rotate clockwise?
Homework Statement
3x^2 - 2\sqrt{3}xy +y^2 = 1
Homework Equations
x = x'\cos\alpha - y'\sin\alpha
y = x'\sin\alpha + y'\cos\alpha
The Attempt at a Solution
The discriminant test is
4(3) - 4(3)(1) = 0
Supposed to be a parabola, instead we get lines.
One other thing
Supposed that in
cot2\alpha = \frac{A - C}{B}
And then we get that \alpha < 0, can that happen? Can we rotate clockwise?