Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Two questions on electric potential

  1. Oct 1, 2005 #1
    Particle of mass, m, charge q>0 is projected toward a nucleus of charge +Q assumed to be at fixed postiion/
    a) If the aim is perfect then how close to the center of the nucleus will the particle reach when it comes to a halt?

    [tex] q(V_{f} - V{i}) = K [/tex] Vi = 0
    [tex] q \frac{1}{4 \pi \epsilon_{0}} \frac{qQ}{r} = K [/tex]
    [tex] r = \frac{Qq^2}{4 \pi \epsilon_{0} K} [/tex]

    am i correct with the formula for V?

    With a particular imperfect aim the particle reaches twice the distnace as above. Calculate the initial velocity.
    So i imply plug r = 2r into the first answer and break K = 1/2 mv^2 and solve for v?

    A charge per unit length lambda is distributed uniformly along a thin rod of length L.
    a) Determine the potential at a point P at a distnace y from one end of the rod, in line with the rod.

    so [tex] V = \frac{1}{4 \pi \epsilon_{0}} \int_{s=0}^{s=L} \frac{dq}{y+s} [/tex] [tex]
    dq = \lambda ds [/tex]
    and [tex] V = \frac{1}{4 \pi \epsilon_{0}} (\ln{y+L} - \ln{y}) [/tex]
    [tex] V = \frac{Q}{4 \pi \epsilon_{0} L} \ln{\frac{y+L}{y}} [/tex]
    b)Use the result to determine the resulting electric field
    Since the rod is thin no X or z components
    [tex] E = \frac{\partial V}{\partial y} = \frac{Q}{4 \pi \epsilon_{0} y(y+L)} [/tex]
    am i correct?

    Attached Files:

    Last edited: Oct 1, 2005
  2. jcsd
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook

Can you offer guidance or do you also need help?
Draft saved Draft deleted