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Two Sliders, work and energy

  1. Apr 21, 2009 #1
    1. The problem statement, all variables and given/known data

    Each of the sliders A and B has a mass of 2 kg and moves with negligible friction in its
    respective guide, with y being in the vertical direction (see Figure 3). A 20 N horizontal force
    is applied to the midpoint of the connecting link of negligible mass, and the assembly is
    released from rest with θ = 0°. Determine the velocity vA with which slider A strikes the
    horizontal guide when θ = 90°.
    [vA = 3.44 m/s]

    tutorial12.jpg


    2. Relevant equations

    1/2 mv^2

    F = ma

    Wp = mgh

    SUVAT


    3. The attempt at a solution

    When at 0 degrees

    W=0J

    At 90

    F=20N

    W = 20xd = 8J

    Work from cart A = 0.5mv^2

    Therefore 16 = mv^2

    v = 2 rt2

    Or...

    do i need to add the energy from 20n force and from cart b...

    0.5mv^2 (b) + 8J = 0.5mv^2 (A)

    with F = ma, 20/10 a = 10 therefore v (b) = 2 rt 2

    sub this into above eq.

    8 + 8 = 0.5mv^2

    v = 4

    Help!

    Iv been goin round in circles, clearly im wrong lol can someone explain how i could work this out please
     
  2. jcsd
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