Two identical stones are dropped from a tall building, one after the other. Assume air resistance is negligible. While both stones are falling, what will happen to the vertical distance between them?
a) It will increase.
b) It will first increase and then remain constant.
c) It will remain the same.
d) It will decrease.
The Attempt at a Solution
Assuming air resistance in negligible, wouldn't the stones both be affected equally and fall to the ground at the same rate of gravitational pull? They would both fall at the rate of 9.81m/s^2 and thus the distance between them would remain the same? Or would it increase until both were falling at this rate and then remain equal?
The book says that the answer is "It will increase" but that would mean that two things being affected by the same force have different accelerations? Why is this?