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2 stones are dropped off a 60 m cliff the second stone is droped 1.6 s after the first one. how far below the top of the cliff is the second stone when th seperation between the 2 stones is 36 m?
so i am trying to use the equation x1=xo+tvo+.5at^2
then x2=xo+(t+1.6)vo+.5a(t+1.6)^2
or should i set my zero point somewhere else like where stone 2 is when the distance between the stones is 36 m?
please give me a lead
so i am trying to use the equation x1=xo+tvo+.5at^2
then x2=xo+(t+1.6)vo+.5a(t+1.6)^2
or should i set my zero point somewhere else like where stone 2 is when the distance between the stones is 36 m?
please give me a lead