# U = 2yz/x, v= 3zx/y Jacobians

1. Oct 26, 2013

I need the solution for this If u = 2yz/x, v= 3zx/y, w= 4xy/z Show that ∂(x,y.z)/∂(u,v,w) = 1/96. Please

2. Oct 26, 2013

### HallsofIvy

Staff Emeritus
What, exactly, is your difficulty? Do you know what the "Jacobian" is? Do you know how to find the partial derivatives.

Perhaps the difficulty is that you are given u, v, and w as functions of x, y, and z but are asked for $\partial(x, y, z)/\partial(u, v, w)$ rather than $\partial(u, v, w)/\partial(x, y, z)$? Not to worry!
$$\dfrac{\partial(x, y, y)}{\partial(u, v, w)}= \dfrac{1}{\dfrac{\partial(u, v, w)}{\partial(x, y, z)}}$$

3. Oct 26, 2013

Yes I do know how to find. Yes I have given function w.r.t x, y, z as it was given in the problem to find the same as above. Thanks for the reply

4. Oct 26, 2013

### HallsofIvy

Staff Emeritus
Excellent! Problem solved.

5. Feb 15, 2014