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## Homework Statement

A U shaped tube, open to the air on both ends, contains mercury. Water is poured into the left arm until the water column is 10 cm deep. How far upward from its intitial position does the mercury in the right arm rise?

## Homework Equations

## The Attempt at a Solution

h is the height of mercury on the left side of the tube

x is the distance that the mercury moves up

101300 Pa + (1000kg/m^3)(9.80)(.10m) + (13600kg/m^3)(9.80)h= 101300 Pa + (13,600kg/m^3)(9.80)(h+x)

980 + 133280h = 133280h + 133280x

980=133280x

x= .00735m = .735cm I'm not sure if I did this correctly--this answer seems quite small