A U shaped tube, open to the air on both ends, contains mercury. Water is poured into the left arm until the water column is 10 cm deep. How far upward from its intitial position does the mercury in the right arm rise?
The Attempt at a Solution
h is the height of mercury on the left side of the tube
x is the distance that the mercury moves up
101300 Pa + (1000kg/m^3)(9.80)(.10m) + (13600kg/m^3)(9.80)h= 101300 Pa + (13,600kg/m^3)(9.80)(h+x)
980 + 133280h = 133280h + 133280x
x= .00735m = .735cm I'm not sure if I did this correctly--this answer seems quite small