U-Substitution involving cos

  • Thread starter 01010011
  • Start date
  • #1
01010011
48
0
Hi,
For this integration by substitution problem, I am not sure whether I should:

1. simplify the problem first, then select U, find the derivative of U, then integrate

or

2. use the product rule first (on the upper part of the equation), then select U, then find the derivative of U, then integrate,

or

3. if I could just cancel like terms first, and be left with cos to integrate

Homework Statement



Evaluate the indefinite integral

Homework Equations



integral of cos * (square root of t) / (square root of t) dt

The Attempt at a Solution



integral of cos * (square root of t) / (square root of t) dt

integral of [cos t^(1/2)] / t^(1/2) dt

let U = cos t ^ 1/2

du = 1/2 (sin t 3/2) / (t 3/2)

Now I am really lost! What should I do?
 

Answers and Replies

  • #2
Count Iblis
1,859
7
Try t = x^2
 
  • #3
01010011
48
0
Try t = x^2

Thanks for your reply Count Iblis. How does x come in this?
 
  • #4
Lunat1c
66
0
It's just a variable name. If you prefer to use 'u' instead, make it t = u^2.
 
  • #5
01010011
48
0
Still trying to figure out what you mean by t = u^2.

Up to where was I right?
 
  • #6
Lunat1c
66
0
t = u^2 means you're going to use the substitution u = sqrt(t) to evaluate your integral. I'm pretty sure you can continue from there
 

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