(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A U tube of uniform cross sectional area A and base length 'L' contains a liquid of density "p". It is rotated about one of its vertical limbs with constant angular velocity [tex]\omega[/tex]. If the diameter of the tube is small compared to the base length, find the difference in levels of liquids in the to limbs.

3. The attempt at a solution

the shift will be because of the force exerted by the rotation on the liquid contained in the base.

I integrate to find this force [I am not posting the integration, because I think its right, if your answer dos not match with mine, tell me I will post my working on this integration.]

The force on the liquid in th base=[tex]\frac{Ap\omega^{2}L^{2}}{2}[/tex]

Now the work done by this force = change in potential energy due to rise of liquid in one limb

[tex]\frac{Ap\omega^{2}L^{2}}{2} * h = \frac{AP h^{2}g}{2}[/tex]

Is this step right to find "h"?????

I was also thinking what is the net work done on water. Is it zero, because the rise in one limb=fall in the other????

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: U tube question:

**Physics Forums | Science Articles, Homework Help, Discussion**