UCM problem

  • Thread starter Morhas
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Homework Statement



A 1.2 m long pendulum reaches a speed of 4.0 m/s at the bottom of its swing.
http://members.shaw.ca/barry-barclay/Self-Tests/test07/q02.gif
What is the tension in the string at this position?

Homework Equations



Fnet=Mv^2/r

The Attempt at a Solution



Im my FBD I had FT acting up, and fg acting down.

Ft-Fg=mv^2/r
Ft-mg=mv^2/r
Ft -(9.8)(3)=(3)(4.0)^2/(1.2)
Ft=40 +(9.8)(3.0)

EDIT Realized my mistake less than a second after posting this. :) Mods can delete.
 

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