- #1

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(-infinity, n) or [n, infinity) it is not going to be unbounded.

The other thing that I was wondering is can a set be neither open nor closed AND unbounded? Doesn't the definition of open/closed imply that there is a boundary?

Thanks!

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- Thread starter BelaTalbot
- Start date

- #1

- 3

- 0

(-infinity, n) or [n, infinity) it is not going to be unbounded.

The other thing that I was wondering is can a set be neither open nor closed AND unbounded? Doesn't the definition of open/closed imply that there is a boundary?

Thanks!

- #2

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- #3

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Is a bounded set synonymous to a set that goes to infinity?

No and furthermore the bound does not even have to be a member of the set.

A set can have lots of bounds, even an infinite number of them.

A bound can be 'above' or 'below'.

An upper bound is simply a real number that is either greater than or equal to every member of the set or less than/equalto every member of the set.

so 7,8,9,10 etc all form upper bounds to the set {2,3,4,5,6} ; none are memebrs of the set.

but wait 6 also forms an upper bound as it satisfies the equal to and is a member.

Similarly 1,0,-1,-2 all form lower bounds that are not members and 2 forms a lower bound that is

Sets which 'go to infinity' are unbounded. However a set can contain an infinite number of members and still be bounded, above and/or below.

for example the set {1/1, 1/2, 1/3, .....} is bounded above by 2 ,1 etc and bounded below by 0, -1 etc, but contains an infinite number of members.

The set [tex]\{ - \infty ,..... - 2, - 1,0,1,\frac{1}{2},\frac{1}{3},.......\} [/tex]

is not bounded below but is bounded above.

If a set has both a lower and upper bound so that the modulus of any member, x, is less than or equal to some real number K then the set is bounded. (No upper or lower)

If for any [tex]x \in S[/tex] there exists a K such that

[tex]\left| x \right| \le K[/tex]

The set S is bounded.

Hope this helps.

- #4

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"bounded" does not mean "has a boundary"

Isn't English confusing?

Isn't English confusing?

- #5

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- #6

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Any finite set S of real numbers is bounded.

Infinite sets can be bounded or unbounded.

Remember that to be bounded a set must have**both** a lower bound and an upper bound.

Sets with only a lower or upper bound are unbounded.

A further question for you to ponder:

Can a set of complex numbers be bounded?

Infinite sets can be bounded or unbounded.

Remember that to be bounded a set must have

Sets with only a lower or upper bound are unbounded.

A further question for you to ponder:

Can a set of complex numbers be bounded?

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