- #1
alejandrito29
- 150
- 0
For the ground state of harmonic oscillator i have
[tex] \Delta p \Delta x =\frac{\hbar}{2}[/tex]
why if i do
[tex]\frac{1}{F} \Delta p \Delta x \cdot F =\frac{\hbar}{2}[/tex]
[tex] \Delta t \Delta E = \frac{\hbar}{2} [/tex]
[tex] \Delta E = \frac{\hbar}{2} \frac{1}{\Delta t} [/tex]
[tex] \Delta E = \frac{\hbar}{2} f [/tex]
but my answer should be [tex] \Delta E = \frac{\hbar}{2} \omega [/tex] ?
[tex] \Delta p \Delta x =\frac{\hbar}{2}[/tex]
why if i do
[tex]\frac{1}{F} \Delta p \Delta x \cdot F =\frac{\hbar}{2}[/tex]
[tex] \Delta t \Delta E = \frac{\hbar}{2} [/tex]
[tex] \Delta E = \frac{\hbar}{2} \frac{1}{\Delta t} [/tex]
[tex] \Delta E = \frac{\hbar}{2} f [/tex]
but my answer should be [tex] \Delta E = \frac{\hbar}{2} \omega [/tex] ?