1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Uncertainties homework problem

  1. May 7, 2012 #1
    1. The problem statement, all variables and given/known data

    let a=360.9±0.1, let b=180.4±0.1, let c=212.5±0.13 and let d=211.7±0.16

    whats f (including uncertainty) where

    f-1 = ((a/b)-1)/((c/d)-1)

    2. Relevant equations

    add the percentage uncertainties in quadrature if dividing two variables
    add the absolute uncertainties in quadrature of adding two variables????


    3. The attempt at a solution

    from plugging in the numbers f=1.0038

    the percentage uncertainty for a is 0.03%
    the percentage uncertainty of b is 0.06%
    adding this in quadrature gives 0.07% (call this y)

    the percentage uncertainty for c is 0.063136037%
    the percentage uncertainty of d is 0.077617746%
    adding this in quadrature gives 0.1% (call this z)

    now find the uncertainty of the quotient of these is adding y and z in quadrature giving 0.12%

    therefore f=1.0038±0.0012


    is this correct?!

    thanks
     
  2. jcsd
  3. May 7, 2012 #2

    gneill

    User Avatar

    Staff: Mentor

    Re: uncertainties

    Why f-1? Why isn't the relationship specified as f = ...
    Or is the -1 supposed to be an exponent? Are the other -1's also exponents?
    I'm not seeing how you arrive at this number from the initial values and relationship. Can you elaborate, perhaps break down and present the calculation in smaller steps?
     
  4. May 7, 2012 #3
    Re: uncertainties

    I stupidly typed in the wrong equation its meant to be:

    f-1 = ((c/d)-1)/((a/b)-1)

    It just gives it as f-1 =... it could equally be:

    f=1+(((c/d)-1)/((a/b)-1)). You dont know where the uncertainties come from either? i just added it in quadrature eg

    does that make more sense? Do you understand where the uncertainties comes from?

    thanks
     
  5. May 7, 2012 #4

    gneill

    User Avatar

    Staff: Mentor

    Re: uncertainties

    Okay, with your correction I can now see what's what.

    Your method looks okay to me, and the result appears to be reasonable. You might want to keep a couple more decimal places in intermediate results and round the final value only at the end.

    As a check I calculated the uncertainty using another method (partial differentials) and arrived at a value very close to yours.
     
  6. May 7, 2012 #5
    Re: uncertainties

    great, thanks!! I have a difficulty with uncertainties. I have another general question, if you dont mind - I am trying to give an estimate of the half value layer of xrays going through aluminium. From a graph I have determined the half value layer to be 3.03mm

    Im now trying to give an estimate of the error. Here are the sources of uncertainty i have come up with:

    Repeatability of output - 1%
    Influence of scatter - 1%
    electrometer - response 0.5\%
    scale reading 0.01
    standard deviation - calculated as usual

    effect on environment - temperature 1.6\%
    - pressure neglible
    Aluminium thickness - 0.05mm (1.7\%)

    can I just add the percentage errors in quadrature and so get an overal uncertainty of 3.17% and thus get an answer of (3.03±0.1)mm??

    or do i do it another way. I have spent hours searching the internet but Im just getting really confused!!

    thanks
     
  7. May 7, 2012 #6

    gneill

    User Avatar

    Staff: Mentor

    Re: uncertainties

    If the sources of error all contribute to a single measurement and they are truly independent of each other, then yes, add them in quadrature. If your plotted values are the result of calculations on several measured values that are affected individually by these things, then apply the rules for combining uncertainties according to the equation(s) used.
     
  8. May 8, 2012 #7
    Re: uncertainties

    so its not the absote uncertanties you add?

    Ive just thought -

    if im just plottng the graph with all the error bars and I want to quote the result from the graph - not the equaton i.e. i just look to see where ts half the ntensty and quote the correspondng depth. whats the uncertanty there. a combinaton of the uncertanties described previously or smply the scale reading error on the graph?

    because the expermental errors is to do wth measurng the indvidual points, not how accurately i can measure my graph...

    thanks
     
  9. May 8, 2012 #8

    gneill

    User Avatar

    Staff: Mentor

    Re: uncertainties

    Usually the graph points are plotted with error bars and a least-squares type of curve fit is done. Presumably there's curve plotting software that will take the individual point uncertainties into account, but I'm not familiar enough with what's available to make a recommendation.

    If you draw the curve by hand then you're 'connecting the dots' by eye, making a smooth curve that passes within the error bars from all the points. This is a type of averaging/estimating that's hard to characterize precisely. I suppose for the uncertainty you could then make an estimate from the size of the error bars in the neighborhood of the point in question.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Uncertainties homework problem
  1. Uncertainty Problem (Replies: 9)

  2. Uncertainty problem (Replies: 1)

  3. Uncertainty Problem (Replies: 6)

Loading...