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## Homework Statement

If the relative error of m is 1% and of h is .5%, what is the error of log(mh)?

## Homework Equations

d/dx(lnx)=1/x, [tex]\delta[/tex]lnx=[tex]\delta[/tex]x/x

## The Attempt at a Solution

[tex]\delta[/tex](ln0.43(mh))=[tex]\delta[/tex](0.43lnm + 0.43lnh)

=[tex]\delta[/tex](0.43ln0.01 + 0.43ln0.005)

=-4.26

i'm pretty sure this isn't right since it's a negative number, i have no idea how to do this