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Uncertainty in labs

  1. Sep 25, 2008 #1
    *Actual yield of C₉H₈O₄: 0.11 g ± 5,8%
    *Theoretical yield of C₉H₈O₄: 0.25 g

    *Percent yield: (0.11/0.25)x100 = 43% ± 5,8%

    Have I done anything wrong when taking the percent error down?
  2. jcsd
  3. Sep 25, 2008 #2


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    Thought this might help.
  4. Sep 29, 2008 #3
    The equation to find % error is

    (abs(theoretical - measured/actual)/theoretical)*100=%error

    abs=absolute value
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