1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Uncertainty in the volume

  1. Sep 7, 2013 #1
    1. The problem statement, all variables and given/known data
    As you eat your way through a bag of chocolate chip cookies, you observe that each cookie is a circular disk with a diameter of 8.50 ± 0.02 cm and a thickness of 0.050 ± 0.005 cm. (a) Find the average volume of a cookie and the uncertainty in the volume. (b) Find the ratio of the diameter to the thickness and the uncertainty in this ratio.


    2. Relevant equations
    V=pi*r2*h
    d=8.50 +/- 0.02 cm → r=4.25+-0.01 cm

    3. The attempt at a solution
    a.) average volume V=pi*r^2*h=pi*(4.25cm)2*0.050cm≈2.8cm3

    volume of the smallest cookie V=pi*(4.24cm)2*0.045cm=2.54152...cm3
    volume of the biggest cookie V=pi*(4.26cm)2*0.055cm=3.1356...cm3
    uncertainty= (biggest - smallest)/2=0.30cm3
    b.) ratio of the diameter to the thickness= 8.50cm/0.050cm=170
    uncertainty=biggest ratio-smallest ratio=8.52cm/0.045cm-8.48cm/0.055cm=35
    Please check my answers. I am not sure what is meant with that uncertainty thing.
     
    Last edited: Sep 7, 2013
  2. jcsd
  3. Sep 7, 2013 #2

    gneill

    User Avatar

    Staff: Mentor

    The idea is that an actual value of a given quantity must lie between the biggest and smallest values and the assumption is made that it will most likely be right in the middle of that range. Half the spread should be "to the left" and half should be "to the right" of the average value. So, divide the total range by two to yield the uncertainty. In other words for f ±Δf you want:
    $$Δf = \frac{f_{big} - f_{small}}{2}$$

    In part b, check the thickness value you've used for the "biggest" term.
     
  4. Sep 7, 2013 #3
    So now the volume could be expressed as V=2.8 +-0.30cm3 ?
     
  5. Sep 7, 2013 #4

    gneill

    User Avatar

    Staff: Mentor

    V = 2.8 ± 0.3 cm3

    Don't add a '0' past the digit you've rounded! That would imply another digit of accuracy, but you've already disposed of it by rounding.
     
  6. Sep 7, 2013 #5
    Could you please elaborate?
     
  7. Sep 7, 2013 #6

    gneill

    User Avatar

    Staff: Mentor

    You wrote:
    Shouldn't that be 0.045 cm?
     
  8. Sep 7, 2013 #7
    Yes it should! A typo. Thanks. Is b otherwise correct or should it be 35/2?
     
    Last edited: Sep 7, 2013
  9. Sep 7, 2013 #8

    gneill

    User Avatar

    Staff: Mentor

    Not correct. Redo the calculation and remember what I said about dividing the result in half.
     
  10. Sep 7, 2013 #9
    I appreciate your help. However, I still don't know what was the whole exercise for. :smile:
     
    Last edited: Sep 7, 2013
  11. Sep 7, 2013 #10

    gneill

    User Avatar

    Staff: Mentor

    The idea of uncertainty values is to establish a range over which the results of calculations may lie when they are derived from imperfect data. Every measurement has an error associated with it -- no measurement is ever perfectly accurate.

    You will use uncertainty calculations a LOT in the sciences, particularly if you have to do labs and the associated lab reports.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted