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## Homework Equations

E=mc^2

E = p^2/2m

Δx.Δp ≥ h/4π

## The Attempt at a Solution

So I got the mass rearranging E = mc^2

m = 5*1.6*10^-19 / (3*10^8)^2

m = 8.88*10^-36 kg

then Δp = √(2mE)

which = 3.77*10^-27 kg m s^-1

Finally

Δx ≥ h/(4*pi*3.77*10^-27)

= 14nm

My only problem is that this nucleus is greater than the hydrogen atom. So shouldn't its ionisation energy be greater than 13.6 eV?

Thanks for anyone that can help.