In an atom, an electron is confined to a space of roughly 10^-10 meters. If we take this to be the uncertainty in the electron's position, what is the minimum uncertainty in its momentum?(adsbygoogle = window.adsbygoogle || []).push({});

delta(x)delta(p)>h (this is how it was derived in the previous parts to the problem)

Ok so i know px = mvx and m = 9.11X10^-31 kg and that delta px = 10^-10(px). I guess where i am stuck is, what do i do with the velocity term?

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# Homework Help: Uncertainty question

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