Under root -i

  • Thread starter mohamen
  • Start date
  • #1
8
0
wat is under root - i ???

please anser this
 

Answers and Replies

  • #2
Hurkyl
Staff Emeritus
Science Advisor
Gold Member
14,950
19
Do you mean [itex]\sqrt{-i}[/itex]? You can figure it out yourself! If [itex]a + bi = \sqrt{-i}[/itex], then what does the definition of square root tell you?
 
  • #3
dextercioby
Science Advisor
Homework Helper
Insights Author
13,147
708
HINT:

[tex] -i=e^{-\frac{i\pi}{2}+2k\pi} , \ k\in\mathbb{Z} [/tex]

Daniel.
 
  • #4
Gib Z
Homework Helper
3,346
6
Hey guys, dont post here often, i will more from now on. Anyway, dexter got that from the identity e^(ix)= cos x + i sin x.
 
  • #5
8
0
will it be solved by the de mouvies theorm..........i dont think so...
 
  • #6
dextercioby
Science Advisor
Homework Helper
Insights Author
13,147
708
You mean "de Moivre". Yes, it will, since that theorem is a trivial consequence of the fact that

[tex] \left(e^{ix}\right)^{n}=e^{inx} [/tex]

Daniel.
 
  • #7
HallsofIvy
Science Advisor
Homework Helper
41,847
966
will it be solved by the de mouvies theorm..........i dont think so...
I personally like Hurkyl's suggestion best but WHY don't you think deMoivre's formula will work? It can be used to find any root of any complex number.
 

Related Threads on Under root -i

Replies
4
Views
2K
  • Last Post
Replies
2
Views
2K
  • Last Post
Replies
4
Views
2K
  • Last Post
Replies
3
Views
2K
  • Last Post
Replies
16
Views
4K
  • Last Post
Replies
9
Views
967
  • Last Post
Replies
2
Views
5K
Replies
6
Views
2K
Replies
1
Views
3K
Top