Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Understanding correlations in a pair of two level systems

  1. Feb 10, 2013 #1
    Hi,

    I have a rather silly question so forgive me for that. Suppose I have two two-level atoms. Now, I have a state of the system and I can find the excited state population of the first atom by taking the expectation value [itex]\left\langle\frac{1+\sigma_{1}^{z}}{2} \right\rangle [/itex] and similarly for the second atom.

    However, if I want to find the probability that both atoms are excited, we need to look at the expectation value of the operator [itex]\left\langle\frac{1+\sigma_{1}^{z}}{2}\otimes\frac{1+\sigma_{2}^{z}}{2}\right\rangle[/itex] which is not the product of expectation values calculated earlier because we now have a term of the form [itex]\left\langle\sigma_{1}^{z}\otimes\sigma_{2}^{z} \right\rangle [/itex]

    Thus, if we have the identity and the three Pauli matrices as a basis for the operators on each atom, I get a total of 16 operator combinations. I need to therefore have 16 numbers to fully characterize my system. Discounting the trivial [itex]\left\langle1\otimes1\right\rangle [/itex], that leaves 15 numbers.

    My question is, are these fifteen numbers fully independent of each other? For instance, if I have both my atoms in the excited state, then isn't [itex]\left\langle\sigma_{1}^{z}\otimes\sigma_{2}^{z} \right\rangle [/itex] also determined? Or more generally, can I choose any fifteen numbers between -1 and 1 and still have it correspond to a physical state?

    Thank you :)
     
  2. jcsd
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Can you offer guidance or do you also need help?
Draft saved Draft deleted



Similar Discussions: Understanding correlations in a pair of two level systems
  1. Two level system (Replies: 2)

Loading...