Understanding the Relationship Between Angle and Magnetic Force

In summary, the problem is asking for the angle at which a charged particle will experience a magnetic force of 1.5 times the magnitude it experiences at an angle of 16° with respect to a magnetic field. The formula qvBsin(theta) is used to solve this problem, and the angle can be found by setting 1.5qvBsin(16) equal to qvBsin(theta).
  • #1
osustudent2010
17
0
Hi, I am having trouble with my last physics homework question (below):

When a charged particle moves at an angle of 16° with respect to a magnetic field, it experiences a magnetic force of magnitude F. At what angle (less than 90°) with respect to this field will this particle, moving at the same speed, experience a magnetic force of magnitude 1.5F?

I'm not sure how to solve it. I've tried using F(mag)= qvB (paralell)

But this doesn't work! Any help would be appricated (ASAP)!
 
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  • #2
You know that F = qv (cross) B, or qvBsin(theta).

qvBsin(16) is F1

1.5F1 = F2
1.5F1 = 1.5qvBsin(16)

F2 = qvBsin(theta)


So basically you want to solve 1.5qvBsin(16) = qvBsin(theta)

The problem states that q,v, and B are constant.
 
  • #3


Hi there,

Thank you for reaching out for help with your physics homework question. It seems like you are on the right track with using the equation F(mag) = qvB (parallel). However, there are a few steps you need to take to solve this problem.

First, we need to find the relationship between the angle of the particle and the magnitude of the magnetic force. This can be done by using the trigonometric function sine. Since we know the angle is 16°, we can use the equation sin(16°) = F/1.5F to find the angle that will result in a magnetic force of 1.5F. This gives us an angle of approximately 24.5°.

Next, we can use this angle in the F(mag) = qvB (parallel) equation to solve for B. Since the speed and charge of the particle are constant, we can set up a ratio of the magnetic forces at the two angles:

F(mag)1.5F = qvB(sin(24.5°)) / F = qvB(sin(16°))

Solving for B, we get B = 1.5sin(16°)/sin(24.5°) = 0.906 T.

Therefore, at an angle of approximately 24.5° with respect to the magnetic field, the particle will experience a magnetic force of 1.5F. I hope this helps and if you have any further questions, please don't hesitate to ask. Good luck with your homework!
 

1. What is magnetic force?

Magnetic force is a force that is exerted between two magnets or between a magnet and a magnetic material. It is caused by the interaction of magnetic fields.

2. How does magnetic force work?

Magnetic force is the result of the attraction or repulsion between the poles of magnets. Opposite poles (north and south) attract each other, while like poles (north and north or south and south) repel each other.

3. What are the properties of magnetic force?

Magnetic force has several properties, including the ability to attract or repel, the ability to act at a distance, and the ability to influence the motion of charged particles.

4. What are some real-life applications of magnetic force?

Magnetic force is used in a variety of everyday objects and technologies, such as electric motors, generators, speakers, credit cards, and MRI machines. It is also used in compasses for navigation.

5. How is magnetic force related to electricity?

Magnetic force and electricity are closely related and are both part of the electromagnetic force. Moving electric charges create magnetic fields, and changing magnetic fields can induce electric currents. This relationship is described by Maxwell's equations.

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