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Understanding Yield

  1. Sep 1, 2007 #1
    Is this how it works??? :

    BE(product) - BE(reactant#1) - BE(reactant#2) => Yield from fusion of product

    Easy enough, but what if reactant#1 and/or reactant#2 are also products of fusion?? Does the equation need to be broken down even further, or is the final BE for the final reactants all that is needed?
    Last edited: Sep 1, 2007
  2. jcsd
  3. Sep 3, 2007 #2
    This WAS a question---not sure if the above is correct.
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