- #1

- 26

- 0

y''-4y'+4y=2e^2x

I tried assuming the yp to be Ae^2x but when I plugged it into the DE I ended up with 0=2e^2x

??

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- Thread starter s7b
- Start date

- #1

- 26

- 0

y''-4y'+4y=2e^2x

I tried assuming the yp to be Ae^2x but when I plugged it into the DE I ended up with 0=2e^2x

??

- #2

rock.freak667

Homework Helper

- 6,223

- 31

Since '2' double root of your aux. eq'n.

the yp should be Ax^2e^2x

the yp should be Ax^2e^2x

- #3

- 26

- 0

Once you substitute back into the original DE

Do you get:

8Ax^2e^2x + 2Ae^2x = 2e^2x

Do you get:

8Ax^2e^2x + 2Ae^2x = 2e^2x

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