If I have some group representation ##D(e)=1##, ##D(s)=1## where ##e\neq s## it is called unfaithfull because it is not isomorphism.(adsbygoogle = window.adsbygoogle || []).push({});

If I denote this group by ##(\{1,1\},\cdot)##. My question is how I treat this set as a two element one, when I have only one element in the set? I'm a bit confused with this.

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# Unfaithful representation

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