a train starts from station a with a uniform acceleration of 5.00 x 10^-1 m/s^2 (east) and attains full speed after 50.0s. It travels at full speed for 1.20 x 10^2 s, then is brought to rest at station b by the application of the brakes which produces a constant acceleration of -2.50 m/s^2 (east). find the distance between station a and station b
The Attempt at a Solution
i tried adding station a and b's displacements but it didn't add up to 3.75x10^3 m (the answer)
i got station a's displacement by finding vfinal then using d=vft-1/2at^2 and added that to the other displacement and yea didn't work.