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Uniform accleration

  1. Sep 2, 2007 #1
    1. An object moving with uniform acceleration has a velocity of 17.0 cm/s in the positive x direction when its x coordinate is 3.00 cm. If its x coordinate 2.60 s later is -5.00 cm, what is its acceleration?




    2.
    [tex]x = x_0 + v_0 t + (1/2) a t^2[/tex]




    3.
    X = 5
    Xo = 3
    V = 17
    Vf = 17
    a = ?
    t = 2.6

    Does these values seem correct? I plug them into the equation above but im not getting the right answer. i got -12.4872 cm/s. what am i doing wrong?
     
  2. jcsd
  3. Sep 2, 2007 #2


    The value you're using for X is wrong—note that the object starts to the right of the origin and ends at the left for this period of time.
     
  4. Sep 2, 2007 #3
    oh man -5!, i thought this whole time it was 5. well this clears up alot of headache
     
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