Uniform circular motion (I DON'T KNOW)

[heelp]

WHAT IS THE MAXIMUM SPEED WITH WHICH A 1050KG CAR CAN ROUND A TURN OF RADIUS 77M ON A FLAT ROAD IF THE COESFFIECENT OF STATIC FRICTION BETWEEN TIRES AND ROAD IS .80? here is what I have so far?

m= 1050kg
r =77m
uk =.080
FN=mg FR =ukfn
(1050kg)(9.8m/s) = FN = 10290N
(.80) (10290) = 8232N= FR
A= F/m a=10290N + 8232N/1050 17.64M/S^2
SPEED = X/T 77/17.64 =4.4m/s
Not sure am I right?

 

[newcool]

At max speed:
F_s = ma
F_s = u_s * N = u_s*mg

Remember that a = v^2/r and solve for v.

 

[heelp]

reply

v= squre root of (9.8m/s^2)(77m) = is the maxium speed 27.46m/s

 

[newcool]

You don't need to know time.

F_s = ma

You know F_s, you know m and you know that a = v^2/r

 

[ranger]

[

v= squre root of (9.8m/s^2)(77m) = is the maxium speed 27.46m/s

Why did you use acceleration = 9.80 m/s/s ?
The car is on a flat surface with acceleration directed along the x-axis. This causes the car to move forward. Force of gravity acts on the y-axis pulling an object downward.

http://www.physicsclassroom.com/Class/circles/U6L2a.html

 

[heelp]

is F_S IS TOTAL Force

 

[ranger]

is F_S IS TOTAL Force

Fnet is simply the sum of all the forces.

Please read this. I'm sure that will help you. Pay special attention to those examples.