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Uniform circular motion

  1. Jun 22, 2008 #1
    1. The problem statement, all variables and given/known data
    A 4.00 kg object is attached to a vertical rod by two strings. The object rotates in a horizontal circle at constant speed 6.00m/s. Find the tension in the upper string and the lower string.
    View attachment phy2.bmp

    2. Relevant equations
    C=2[tex]\pi[/tex]r
    T=(M)V^2)/r


    3. The attempt at a solution[
    The tension should be easy. Since you have the speed and r. and the mass. Will the tension be the same for both strings though????
     
  2. jcsd
  3. Jun 22, 2008 #2

    Hootenanny

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    Although I can't see your attachment I can say that the tension in the two strings, will not, in general be equal. I hope the attachment is a FBD, if it isn't, I suggest that you draw one.
     
  4. Jun 22, 2008 #3
    Anyone help me?? I know the top string has force of Tcos@-Mg in the y direction and Tsin@ in the x direction. I need help on the bottom string would it be pulling the ball down as well so you would have T+MG for y direction and x direction would be TSin@????
     
  5. Jun 23, 2008 #4

    Hootenanny

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    Good :approve:
    You need to be careful here. Firstly with the direction, for the top string you have taken up as positive (i.e. the ball's weight is negative), however for the bottom string you have taken down to be positive (i.e. the ball's weight and the tension in the bottom string is positive). You need to chose one convention and stick to it throughout.

    Secondly, as I said previously, the tensions in the two strings needn't be equal. Therefore, you need to use different symbols for the tension in the upper and lower string, perhaps T1 and T2, as opposed to simply T.

    In addition, instead of considering the string separately, you should consider the forces acting on the ball, which are the tensions of the two strings and it's weight.
     
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