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## Homework Statement

Your calculation is actually a derivation of the centripetal acceleration. To see this, express the acceleration of the particle in terms of its position r(t).

r(t) = [tex]Rcos(\omega t)\textbf{i} + Rsin(\omega t)\textbf{j}[/tex]

## Homework Equations

[tex]v = \omega R [/tex]

[tex]a = \frac{v^2}{R} [/tex]

[tex]a = \omega v [/tex]

## The Attempt at a Solution

[tex]v = \frac{d}{dt}r(t) \times \omega[/tex]

btw, this is a Mastering engineering question, so i submitted and it says that:

The correct answer does not depend on the variables and functions: d, d, r.

is there another way to display this or am i missing something?

thx,