# Uniform distribution setup

• A
Summary:
Random variable uniform on circle. Joint distribution of coordinates?
A random variable is distributed uniformly over a circle of radius R. What does the cdf ##F(x,y)## look like as a function of the Cartesian coordinates? The pdf can be expressed as ##f(x,y)=\frac{\delta(\sqrt{x^2+y^2}-R)}{2\pi R}##, where ##\delta## is Dirac delta function. Integration is confusing.

Office_Shredder
Staff Emeritus
Gold Member
Can you describe in words how F(x,y) relates to the geometry of the circle?

Stephen Tashi
The pdf can be expressed as ##f(x,y)=\frac{\delta(\sqrt{x^2+y^2}-R)}{2\pi R}##, where ##\delta## is Dirac delta function.

Can it really? We have to consider the general definition of a pdf.

As I make it out, the pdf is a measure defined relative to some other measure on a probability space and it is defined as a generalized derivative (i.e. a Radon-Nikodym derivative) of that other measure. So a pdf exists or fails to exist relative to the other measure. If the other measure is taken to be volume in 2-D then it is possible to have a sequence of smaller and smaller volumes that converge to an arc on the circle. The limit of the measures of the volumes is zero, but we don't want the probability of an arc of finite length on the circle to be zero So the measure we seek from a pdf is not absolutely continuous with respect to volume measure. So the Radon-Nikodym theorem does not apply. If a pdf is defined as type of Radon-Nikodym derivative, we have to ask if a Radon-Nikodym derivative can exist (i.e. be defined) in situations where the theorem does not apply.

Of course is practice, we would compute the cumulative distribution ##F(a,b)## by ##\frac{1}{2 \pi R}## times the arc length of the part of the circle contained in ##\{(x,y): x \le a, y \le b\}## However, aren't the partial derivatives of that function always zero? [Edit: I should say "zero or nonexistent"]

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To avoid the delta, how about a thin ring and points uniformly distributed over the ring. The pdf in polar coordinates is ##\frac{1}{\pi (r_2^2-r_1^2)}##. Question: get pdf and cdf in Cartesian coordinates.

Office_Shredder
Staff Emeritus
Gold Member
The cdf really is pretty simple, and I'll reiterate my question. What does ##F(x,y)## mean in terms of the geometry of the circle? What is ##F(0,0)## and what is ##F(1,0)##? Your answer should say something about where those points are relative to the circle.

Office_Shredder
Staff Emeritus
Gold Member
Ok, and the more important general question is what does F(x,y) have to do with the position of the point relative to the circle? Just in words describe it.

F(x,y)=Prob((X< x) and(Y< y))

Should be \le, but Latex didn't work.

Office_Shredder
Staff Emeritus