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Uniform Electric Field

  1. Jan 16, 2008 #1
    1. If the accelerating plates are 1.2cm apart and have a potential difference of 25,000V what is the magnitude of the electric field between them?

    2. E=V/D

    3. E=25,000V/1.2x10^-2m= 2083333.3 V/M
  2. jcsd
  3. Jan 16, 2008 #2
    So, what's the problem? It seems to me that you've already solved it.
  4. Jan 16, 2008 #3
    I didn't know if I got the question right...
  5. Jan 16, 2008 #4
    You did. I checked it on my calculator.
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