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## Homework Statement

A proton (m=1.67x10^-27) is suspended at rest in a uniform electric field E. Take into account gravity and determine E.

## Homework Equations

F

_{E}=|q|E

F

_{g}=mg

## The Attempt at a Solution

F

_{G}= mg

F

_{G}= (1.67x10

^{-27})(9.8)

F

_{G}= 1.64 x 10

^{-26}

Since the force on the proton due to the E field is equal and opposite, then:

F

_{E}=|q|E

F

_{E}/ q= E

(1.64x10

^{-26}) / (1.6x10

^{-19}) = E

1.04x10

^{-9}= E

Is my work correct?