# Uniform Wire Question

1. Feb 20, 2005

### Tom McCurdy

Problem here:
http://www.quantumninja.com/hw/random/problem4.jpg

I was trying to figure out how to go about this problem. So far I have come up with

center of mass=
$$\frac{L}{4}cos\frac{\beta}{2}$$

Torque=t
$$\sum t=I\alpha$$

2. Feb 20, 2005

### Davorak

Are you sure this is right
$$cm = \frac{L}{4}cos\frac{\beta}{2}$$
If $\beta$ goes to zero then the cos will go to one and you will be left with $\frac{L}{4}$ which does not seem right to me for a stright rod.

3. Feb 20, 2005

### Tom McCurdy

I thought that was right

4. Feb 20, 2005

### Tom McCurdy

Actually maybe it would be
L/4*cos(b/2)+L/2
center of mass
$$\frac{L}{4}cos\frac{b}{2}+\frac{L}{2}$$

Last edited: Feb 20, 2005
5. Feb 20, 2005

### Davorak

I am sorry you are right. If beta goes to zero the rod becomes lengh of L/2 and the center of mass would the be a L/4.

6. Feb 20, 2005

### Tom McCurdy

Which one is right the first or 2nd one