1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Uniform Wire Question

  1. Feb 20, 2005 #1
    Problem here:

    I was trying to figure out how to go about this problem. So far I have come up with

    center of mass=
    [tex] \frac{L}{4}cos\frac{\beta}{2} [/tex]

    [tex] \sum t=I\alpha [/tex]
  2. jcsd
  3. Feb 20, 2005 #2
    Are you sure this is right
    [tex]cm = \frac{L}{4}cos\frac{\beta}{2} [/tex]
    If [itex]\beta[/itex] goes to zero then the cos will go to one and you will be left with [itex] \frac{L}{4}[/itex] which does not seem right to me for a stright rod.
  4. Feb 20, 2005 #3
    I thought that was right
  5. Feb 20, 2005 #4
    Actually maybe it would be
    center of mass
    [tex] \frac{L}{4}cos\frac{b}{2}+\frac{L}{2} [/tex]
    Last edited: Feb 20, 2005
  6. Feb 20, 2005 #5
    I am sorry you are right. If beta goes to zero the rod becomes lengh of L/2 and the center of mass would the be a L/4.
  7. Feb 20, 2005 #6
    Which one is right the first or 2nd one
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook