# Uniformly Charged Ring problem

1. Dec 9, 2006

### defineNormal

ok here goes,

A uniformly charged ring has a radius equal to 10.0cm and a total charge of +12.0nC. An electron is placed on the ring's axis at a distance of 25.0cm from the center of the ring and is constrained to stay on the axis of the ring. The electron when it reaches the center of the ring?

ok so
Q=+12.0nC
r=0.10m
x=0.25m

here's what I got so far

dE=Ke*dq/r^2
r=(x^2+a^2)^(1/2)
<after integration>
=Ke^x/(x^2+a^2)^(3/2)
I can't figure out how to find Ke> Am I heading in the right direction?

2. Dec 9, 2006

### Andrew Mason

I am not sure what the question is. Is it: "what is the speed of the electron when it passes through the centre of the ring"?

If so, try using electric potential. What is the potential energy at a distance d along the axis? What is the potential energy at the centre of the ring? What is the difference? That has to be the kinetic energy of the electron.

AM

3. Dec 10, 2006

### defineNormal

woops, determine speed :)

4. Dec 11, 2006

### defineNormal

Ok this is what I got Ke(Q/(x^2+a^2) <--- square root over the donominator.
Q= 12.0 nC
a= 25.0cm => 0.25m
r= 10.0cm => 0.10m

the answer given is 1.19x10^7, I keep getting 1.488x10^12, however I see where I wen't wrong because Ke=8.99x10^9 Nm^2/C^2, so this means I have to convert 12.0 nC to C, and I don't know how???

5. Dec 11, 2006

### OlderDan

I assume if it really is nC it means nanoCoulombs or 10^-9C

6. Dec 11, 2006

### defineNormal

but then the exponants cancel each other out???

7. Dec 11, 2006

### OlderDan

Did you use the charge of the electron? Your equation below is not correct. The RHS is just K, not Ke

Other than that, check your computations. You appear to have the correct distances and the correct PE.