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I'm not really sure where to go with this. I want to treat the rod as an infinite number of point charges but I'm not sure how to calculate (y-component of) the electric field caused by each of these points.

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- Thread starter hmmm
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I'm not really sure where to go with this. I want to treat the rod as an infinite number of point charges but I'm not sure how to calculate (y-component of) the electric field caused by each of these points.

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glad to be of help,

Arpan Roy

royarpan@hotmail.com

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HallsofIvy

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Since this problem is not symmetrical, the horizontal components of the [itex]\vec{E}[/itex] do not cancel. The easiest approach is probably to calculate the vertical ( [itex]\vec{E_y}[/itex] ) component seperately.

Draw a diagram of the situation with the given axis, and choose an arbitrary piece of charge [itex]dq[/itex] of the wire.

Come up with an equation for the corresponding electric field [itex]\vec{dE}[/itex] due to [itex]dq[/itex] at the point (0,3).

Figure a way to represent [itex]dq[/itex] in terms of [itex]dx[/itex] so you can integrate with respect to x.

(hint: it involves the linear charge density )

Break the equation into the vertical component of [itex]\vec{E}[/itex] and integrate with respect to x

(hint: [itex]\vec{dE_y} = \vec{dE} sin \theta[/itex] where theta is the angle between a line parallel to the x axis and [itex]\vec{E}[/itex] )

(another hint: you will have to come up with an equation for [itex]sin \theta[/itex] in terms of x so you can integrate )

good luck

-MS

Draw a diagram of the situation with the given axis, and choose an arbitrary piece of charge [itex]dq[/itex] of the wire.

Come up with an equation for the corresponding electric field [itex]\vec{dE}[/itex] due to [itex]dq[/itex] at the point (0,3).

Figure a way to represent [itex]dq[/itex] in terms of [itex]dx[/itex] so you can integrate with respect to x.

(hint: it involves the linear charge density )

Break the equation into the vertical component of [itex]\vec{E}[/itex] and integrate with respect to x

(hint: [itex]\vec{dE_y} = \vec{dE} sin \theta[/itex] where theta is the angle between a line parallel to the x axis and [itex]\vec{E}[/itex] )

(another hint: you will have to come up with an equation for [itex]sin \theta[/itex] in terms of x so you can integrate )

good luck

-MS

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