# Uniformly Continuous

## Homework Statement

Is h(x)=x3+1 uniformly continuous on the set [1,infinity)?

## The Attempt at a Solution

Let $$\epsilon$$>0. For each x,y in the set [1,infinity) with |x-y|<$$\delta$$, we would have |(x3+1)-(y3+1)|=|x3-y3|

Now how can I show that this is less than epsilon?

Office_Shredder
Staff Emeritus