Hello,(adsbygoogle = window.adsbygoogle || []).push({});

We haven't covered capacitance in class yet, but our lab involves the use of capacitors, so I thought I'd throw out a general question.

We were asked to use the MOS FET Electrometer to measure charge, and we were given the formula:

Q = CV

Where C is the capacitance, and V is the potential difference. C is measured in Farads and V in volts.

I'm just confused because in the sample calculations provided by the lab handout, we had:

Qinit = CV = 4.7x10^-9 [F] X 30 [V] = 141 [nF]

How come the unit for charge ended up being in nanofarads, and not in coulombs or nanocoulombs or anything like that?

Any clarifications would be appreciated!

**Physics Forums | Science Articles, Homework Help, Discussion**

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Unit Question with Capacitance

**Physics Forums | Science Articles, Homework Help, Discussion**