- #1

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also does 1 cm^3= 1 mL?

i forgot all these units stuff its really bugging up my mind

- Thread starter nemzy
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- #1

- 125

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also does 1 cm^3= 1 mL?

i forgot all these units stuff its really bugging up my mind

- #2

Pyrrhus

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(kg)(m/s^2) = Newton

1 cm^3= 1 mL Yes

1 cm^3= 1 mL Yes

- #3

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So far i got this in my calculations:

(5.316 L*atm) / ( (211.68 kg*m/s^2)+(.0073m^2*atm))

the answer is suppose to be in meters, and from these units i have no idea how it is possible..anyone have any ideas?

- #4

Pyrrhus

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Show your work, by the way, L is liters right?

- #5

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like for example, if u have 8 atm + 3 liters, will it become 11 (atm+liters)?

- #6

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the equation is this:

h=n*R*T/(m*g+Po*A)

n= 1.85 moles

R=gas constant

T= 350 K

A= .00730 m^2

m= 21.6 kg

and Po is atmospheric pressure (1 atm or 1.0135e5 kPa)

- #7

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Absolutely Not!

- #8

Pyrrhus

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- #9

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that last post was directed at the previous post...about adding units

- #10

Pyrrhus

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a Pascal is N/m^2, use that. Also 1 atm = 101325 pascal.

- #11

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5.315975 L*atm / (211.68 N +739.6725 m^2*Pa)

but i am stuck here, how can i cancel out further units? since the bottom is addition, i have no idea what to do from here...am i still allowed to convert the m^2 to liters and cance it out with the top, as well as the Pa with the atm on top?

- #12

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so you have all newtons on the bottom....then instead of using that gas constant...use the one that is J * mol^-1 * K^-1

then you have J / N.....which is meters (change them to their base forms if you want to double check it :) )

- #13

Pyrrhus

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nicely done

- #14

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8.314 J * mol^-1 * K^-1

instead of

8.2057 L * atm * mol^-1 * K^-1

there are a few other forms of the gas constant too, but these are the most commonly used ones.

- #15

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does anyone know a website that has all these info?

- #16

Pyrrhus

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It should be on your textbook, if not try google.

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