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Electrons are ejected from a metal surface with speeds ranging up to 4.71×105 m/s when light with a wavelength of lambda = 628 nm is used. What is the work function (in eV) of the surface?

Alright, money, using the formula: Max Kinetic energy = hf - Eo

where Eo is the work function. You have all the givens, the answer is supposed to be in eV. Now, im not sure whats happening, but im not geting the right answer. To see if im doing something wrong, i got Kinetic energy=1.010485755x10^-19, and hf=-2.5999x10^-21

try it yourself, maybe im screwing up the units

Cheers

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# Homework Help: Units regarding a photoelectric question

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