There's an inclined plane with theta unknown. The frictional coefficient is 0. m1 is higher on the inclined plane than m2. m1 = 1680kg m2 = 152kg Distance between the two: 11mm At what angle of inclination will the 2nd mass begin to slide down the plane? Normally (without 2 objects) I know that net force would have to equal 0 in order for the box to slide down. In other words, it would be Fgx - Ff = Fnet = 0. I first started with this: 1489.6sinθ - 0 = 0 But I know the law of universal gravitation plays a part in this. I was thinking about making the 1489.6sinθ equal to the universal gravitational equation since I have all the variables. 1489.6sinθ = (Gm1m2)/(r^2) Would this be the correct thing to do? If so, I'm confused as to why they would be equal. Thanks.