At what height above the Earth's surface would an object's weight be one half the value at the surface?(adsbygoogle = window.adsbygoogle || []).push({});

W = m(2)g = Gm(1)(m2) / r^2 is the formula I am using.

I found 1/2 weight to be 2.92825 x 10^25

Then I found m(1) to be 1/2gxW (not sure if I should've used 1/2g here or not) and then I did the rearranging and other such things.

I got an answer of 4.4 x 10^7. It seems a bit high to me, but I don't have a great understanding of the concept, lol.

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# Universal Gravitation

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