Universal Gravity Question

In summary, the difference in the masses of planets A and B can be found by using the equation Ma-Mb = (3520 Newtons) * r^2/Gm, where r is the radius of both planets and m is the mass of the robot. The gravitational acceleration at the surface of each planet can be found by using the universal gravitation constant, G, and the distance from the surface to the center of the planet.
  • #1
kasiu
12
0
1. The mass of a robot is 5370 kg. This robot weighs 3520 N more on planet A than it does on planet B. Both planets have the same radius of 1.33 x 10^7 m. What is the difference MA - MB in the masses of these planets?




2. attached picture



3. I was wondering what to do with the 3520 N. Do I find a ratio of weight between the planets and then multiply the original weight by that ratio? Do I need to use (G*mass/radius^2)? I'd appreciate some pointers or hints. I don't need the solution, just help with setting up the equation and understanding what I am looking for.
 

Attachments

  • physics.JPG
    physics.JPG
    2 KB · Views: 359
Physics news on Phys.org
  • #2
kasiu said:
3. I was wondering what to do with the 3520 N. Do I find a ratio of weight between the planets and then multiply the original weight by that ratio? Do I need to use (G*mass/radius^2)? I'd appreciate some pointers or hints. I don't need the solution, just help with setting up the equation and understanding what I am looking for.

I'd say a comparison ratio for the weight of the robot on the two different planets would be a better place to start.
 
Last edited:
  • #3
So,
would I set it up like this:

W_subB + 3520 N = M * (g_subB)
Or
M * (g_subA) = W_subB +3520 N
So, would I solve for the acceleration of planet A to get g_subA and then use 5370 Kg for my M (mass) and solve for W_subB
 
  • #4
kasiu said:
So,
would I set it up like this:

W_subB + 3520 N = M * (g_subB)
Or
M * (g_subA) = W_subB +3520 N
So, would I solve for the acceleration of planet A to get g_subA and then use 5370 Kg for my M (mass) and solve for W_subB

Yeah, I'm going to take back what I said: because of the types of information provided, a comparison ratio won't really help. Write out both weights in terms of the appropriate Mg in one of those equations. Insert the appropriate expressions for g on each planet. You will now be able to factor your equation, with one of the terms being the difference between the planetary masses, which you can solve from there. (I thought initially that the problem set-up would be nicer...)
 
  • #5
How would I find weight?
Would I use the equation attached?
 
  • #6
so:
(5370*acceleration due to gravity) + 3520 N = 5370 * gravity...
that's not right I can see, but how do I find the weight.
I can't solve for acceleration because I don't have the weight of the planet...
I feel confused :(
 
  • #7
kasiu said:
How would I find weight?
Would I use the equation attached?

Your attachment still hasn't been cleared yet. You have

M * (g_subA) = W_subB +3520 N , so replace W_subB also:

M * (g_subA) = M * (g_subA) +3520 N .

How do you find g on each planet? (You mentioned this in your earlier post.) If you put that in for g_subA and g_subB, what do you get?
 
  • #8
I know that the equation has to equal (mass of planet A)-(mass of planet B)
 
  • #9
do i get the acceleration?
 
  • #10
G(Ma)(m)/d^2 - G(Mb)(m)/d^2= N* r^2/Gm

Would I use that
 
  • #11
kasiu said:
I know that the equation has to equal (mass of planet A)-(mass of planet B)

It won't be equal to it, it will let you solve for that.

do i get the acceleration?

How do you find the gravitational acceleration at the surface of a planet? (Have you already written this?)
 
  • #12
so acceleration= F/m
or
a=g=6.67e-11* mass/distance^2
 
  • #13
ooooooh!
I get it so,

Ma-Mb =N* r^2/Gm
So, what I posted before was right :)
thank you so much!

I understand it now!
:):):)
wow, that took me a while
finally my brain made some connections
thanks once again!
 
  • #14
kasiu said:
so acceleration= F/m
or
a=g=6.67e-11* mass/distance^2

The distance in this application is the distance from the surface of the planet to its center, that is, the planet's radius. (Why that is so is due to a theorem of Newton's you may have discussed by now...)

You can save a little writing and use the universal gravitation constant G, instead of writing 6.67e-11, for now.

So you can now use that, for each planet, in this equation:

M * (g_subA) = M * (g_subA) +3520 N .
 
  • #15
kasiu said:
ooooooh!
I get it so,

Ma-Mb =N* r^2/Gm
So, what I posted before was right :)
thank you so much!

I understand it now!
:):):)
wow, that took me a while
finally my brain made some connections
thanks once again!

Provisionally glad to hear it! The equation should be Ma-Mb = (3520 Newtons) * r^2/Gm , m being the robot's mass. (I wasn't sure what your N was supposed to be -- that's the force unit, not a value itself.) So you do need all the info in the problem... You'll get a pretty big number (in kg).
 

1. What is Universal Gravity?

Universal Gravity is a fundamental force of nature that describes the attraction between all objects with mass. It is responsible for keeping planets in orbit around the sun and for the gravitational pull we experience here on Earth.

2. Who first discovered Universal Gravity?

Sir Isaac Newton is credited with discovering Universal Gravity in the 17th century. He developed the famous Law of Universal Gravitation, which states that the force of gravity is directly proportional to the product of the masses of two objects and inversely proportional to the square of the distance between them.

3. How does Universal Gravity compare to other forces?

Universal Gravity is one of the four fundamental forces in nature, along with electromagnetism, the strong nuclear force, and the weak nuclear force. It is the weakest of these forces, but it has an infinite range, meaning it affects all objects with mass regardless of their distance.

4. Is there a formula for calculating Universal Gravity?

Yes, there is a formula for calculating the force of Universal Gravity between two objects. It is F = (G * m1 * m2) / r^2, where F is the force, G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between them.

5. Can Universal Gravity be explained by Einstein's theory of relativity?

Yes, Einstein's theory of relativity provides a more accurate explanation of Universal Gravity compared to Newton's Law of Universal Gravitation. According to Einstein, gravity is not a force but rather a curvature of space-time caused by the presence of mass. This theory has been proven through numerous experiments and observations.

Similar threads

  • Introductory Physics Homework Help
Replies
5
Views
840
  • Introductory Physics Homework Help
Replies
9
Views
941
Replies
2
Views
2K
  • Introductory Physics Homework Help
Replies
4
Views
436
  • Introductory Physics Homework Help
Replies
2
Views
3K
  • Introductory Physics Homework Help
Replies
18
Views
968
  • Introductory Physics Homework Help
Replies
7
Views
2K
  • Introductory Physics Homework Help
Replies
3
Views
5K
  • Introductory Physics Homework Help
Replies
3
Views
1K
  • Introductory Physics Homework Help
Replies
1
Views
729
Back
Top