- #1
RossBlenkinsop
- 60
- 0
- TL;DR Summary
- find the unknown vector
referring to the image
in fig 1 there is a rail carriage subject to an unknown velocity vector Vu (velocity unknown). Vu has a constant velocity Vu in the direction as shown. In the ceiling of the carriage is a light shown in blue and a columnator on the floor.
The rail carriage is sitting on tracks and a person in the rail carriage can measure the velocity of the carriage wrt the tracks
By pure chance the tracks are oriented parallel to Vu
When the columnator was being built the rail carriage was still subject to the unknown velocity vector Vu. The person was instructed to build the columnator directly below the light source which, according to them, they did. According to the person in the carriage the photons from the light shine directly down the columnator, and therefore the columnator must be directly below the light. However as a result of Vu the the columnator is not directly below the light as is must be offset by some degree to allow for the movement of the carriage as a result of Vu.
Once all is set , the columnator is constructed, the person accelerates the rail carriage to multiple constant velocities Vk (velocity known) wrt the tracks. There are three scenarios Vk is less than Vu, Vk is equal to Vu and Vk is more than Vu (see fig 2). I have omitted the person in the carriage for simplicity
By pure chance the rail carriage is going in the opposite direction to Vu. Or the person could try multiple velocities in both directions. either way the result is the same.
As the columnator is offset, by my calculations, when Vk is equal to Vu the columnator will no longer work and when Vk is more than Vu the columnator will no longer work
is that correct ?
in fig 1 there is a rail carriage subject to an unknown velocity vector Vu (velocity unknown). Vu has a constant velocity Vu in the direction as shown. In the ceiling of the carriage is a light shown in blue and a columnator on the floor.
The rail carriage is sitting on tracks and a person in the rail carriage can measure the velocity of the carriage wrt the tracks
By pure chance the tracks are oriented parallel to Vu
When the columnator was being built the rail carriage was still subject to the unknown velocity vector Vu. The person was instructed to build the columnator directly below the light source which, according to them, they did. According to the person in the carriage the photons from the light shine directly down the columnator, and therefore the columnator must be directly below the light. However as a result of Vu the the columnator is not directly below the light as is must be offset by some degree to allow for the movement of the carriage as a result of Vu.
Once all is set , the columnator is constructed, the person accelerates the rail carriage to multiple constant velocities Vk (velocity known) wrt the tracks. There are three scenarios Vk is less than Vu, Vk is equal to Vu and Vk is more than Vu (see fig 2). I have omitted the person in the carriage for simplicity
By pure chance the rail carriage is going in the opposite direction to Vu. Or the person could try multiple velocities in both directions. either way the result is the same.
As the columnator is offset, by my calculations, when Vk is equal to Vu the columnator will no longer work and when Vk is more than Vu the columnator will no longer work
is that correct ?
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