Hey guys,

some insight to the following problem I have here would be helpful.
I need to see if a conveyor is worth upgraded (i.e. see what the output Tonne/per hour is) from a belt 745mm wide, idler pulley 800mm wide... to a 800mm belt and 850mm wide idler pulley.
Lets assume the length of the conveyor is 17m

I have a conveyor with 3 idlers on an angle of 45 deg, and assuming an angle of repose of 25 deg.
currently there is a 18KW motor on there, and lets assume the idler pulley barrel is 300mm. I want to upgrade to a 30KW motor.

How do I go about working out the max possible T p/hr?

i assume i need the speed of the motor, get velocity. Find the volume of the material over the conveyor length?

Any help is appreciated.

Cheers

Baluncore
2021 Award
The rate of material mass flow will be determined by height difference? and conveyor velocity.

Material falling onto the conveyor must be accelerated to the conveyor velocity. KE = ½∙m∙v²

The change in height will require (or release) potential energy proportional to; PE = m∙g∙h

Thanks for that mate,

So assuming I have incline angle of 15 deg. my equation would be:
T p/hr = 3.6 * (cross sectional area of trough) * (belt speed m/s) * (material density) * Cos(15)?

Only problem I have is getting an accurate calc for the cross sectional area of the trough.
How would I do that with idler trough angle of 45 deg
Belt 745 mm
angle of repose for material = 25 deg

cheers

Baluncore
2021 Award
You are confusing yourself by your fixation on the geometry of the conveyor and the density of the material.
So assuming I have incline angle of 15 deg. my equation would be:
T p/hr = 3.6 * (cross sectional area of trough) * (belt speed m/s) * (material density) * Cos(15)?
What is the coefficient 3.6 ?
Where is the acceleration g = 9.8 needed to work out the change in potential energy?

Product has a change of height, the potential energy must be provided. That height change is a fixed critical parameter.
Product must be accelerated to belt speed, that kinetic energy is not recovered. Belt speed is a critical variable.

Baluncore
2021 Award
Length = 17 m. Incline = 15 deg.
Height change, h = 17 * Sin( 15 ) = 4.4 m.

Material flow of 1 kg will require energy, E = KE + PE.
KE = 1/2 * 1kg * v2
PE = 1kg * 9.8 * h
E per kg = ( 1/2 * v2 ) + ( 9.8 * h )

But belt speed, v, is unknown, we still need to know motor RPM.