- #1

- 38

- 0

80 kg student stands 2.0 m from support 1. How much upward force does support 1 exert on the beam?

I first found the weight of the student to be 784N.

so 784N*2cm =F*3cm

F= 522.67N

is this right?

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter guru
- Start date

- #1

- 38

- 0

80 kg student stands 2.0 m from support 1. How much upward force does support 1 exert on the beam?

I first found the weight of the student to be 784N.

so 784N*2cm =F*3cm

F= 522.67N

is this right?

- #2

- 72

- 0

I think this is how it should be done:

(2x784)+(1.5x980) = 3xF

This gives us the value of F(Force on the other support)=1012.67N

Substracting this value from the total downward force(784N+980N) we get the upward force exerted by the support1 be 751.33N

- #3

- 38

- 0

DeathKnight said:

I think this is how it should be done:

(2x784)+(1.5x980) = 3xF

This gives us the value of F(Force on the other support)=1012.67N

Substracting this value from the total downward force(784N+980N) we get the upward force exerted by the support1 be 751.33N

Yes, I forgot to consider the weight of the beam.

Thanks.

Share: