• Support PF! Buy your school textbooks, materials and every day products Here!

Uranium 235 Fission Question

  • Thread starter dav1d
  • Start date
  • #1
65
0

Homework Statement



Another mode in which uranium 235 can undergo fission is U + n -> Te + Zr +n. Calculate the energy change when 1g of uranium 235 undergoes fission in this way. The masses are U=235.04u. n=1.0087u. Te=134.92u. Zr=99.92u.


Homework Equations





The Attempt at a Solution



The mass of the left side is 236.0487u
The mass of the right side is 235.8487u

delta M=-0.2u

E=mc^2
=-0.2u x 9x106 J/kg x(1.66x10^-27kg/u)
=-.2.988x10^-21J/u ? (Please help me with units here!!!)

E1g=-2.988x10^-21J/u x 1g
(Units have failed me here, please tell me where I went wrong...)
 

Answers and Replies

  • #2
Delphi51
Homework Helper
3,407
10
E=mc^2
=-0.2u(1.66x10^-27kg/u)*(3x10^8m/s)²
= 2.99 x 10^-10 Joules per Uranium nucleus.
How many Uranium nucleii fission?
 
  • #3
65
0
For the speed of light, I used 9 x 10^16 J/kg. Can you show the unit analysis for just squaring 3x10^8 m/s ?

To answer your question

1 gram of U-235, the mass of 1 U-235 nucleus is 235.04u given, so 1gram/235.04u=2.5621772x10^21. Then2.99 x 10^-10 x 2.5621772x10^21 = 7.66091009 × 1011 Joules???
 
  • #4
Delphi51
Homework Helper
3,407
10
Pick any energy formula, say E = mgh. So Joule = kg*m/s²*m.
and Joule/kg = m/s²*m = m²/s²

In my calc, I have
E=mc^2
=-0.2u(1.66x10^-27kg/u)*(3x10^8m/s)²
The u's cancel out and the answer is in kg*m²/s²
which is Joules as seen in E = ½mv² or E = mc².
Your answer looks good now. You just wrote the exponent 16 as 6 in the first calc and there is some confusion about where the decimal place is.
 

Related Threads on Uranium 235 Fission Question

  • Last Post
Replies
4
Views
18K
Replies
2
Views
7K
Replies
4
Views
3K
Replies
4
Views
3K
  • Last Post
Replies
12
Views
3K
  • Last Post
Replies
0
Views
2K
Replies
4
Views
1K
Replies
3
Views
6K
Top