- #1

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**Urgent!! About Impedance**

the total ohm of this impedance ( 30+j40 ) is 50ohm.

but wat is the conjugate impedance ?? 30-j40? total ohm is wat?

30+j40 is 50ohm

solution is square root of (30

^{2}+40

^{2})

- Thread starter KnightMars
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- #1

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the total ohm of this impedance ( 30+j40 ) is 50ohm.

but wat is the conjugate impedance ?? 30-j40? total ohm is wat?

30+j40 is 50ohm

solution is square root of (30

- #2

tiny-tim

Science Advisor

Homework Helper

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Hi KnightMars! Welcome to PF!

Yes, the complex conjugate of 30 + 40 jthe total ohm of this impedance ( 30+j40 ) is 50ohm.

but wat is the conjugate impedance ?? 30-j40? total ohm is wat?

30+j40 is 50ohm

solution is square root of (30^{2}+40^{2})

(you simply replace j by -j)

The magnitude of the complex conjugate impedance is always the same as the magnitude of the original impedance (in this case, 50 Ω).

- #3

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ok ths ^^ done my homework ^^ hehe

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